(4x-3)(2x^2+3x+5)=

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Solution for (4x-3)(2x^2+3x+5)= equation: 


Simplifying
(4x + -3)(2x2 + 3x + 5) = 0

Reorder the terms:
(-3 + 4x)(2x2 + 3x + 5) = 0

Reorder the terms:
(-3 + 4x)(5 + 3x + 2x2) = 0

Multiply (-3 + 4x) * (5 + 3x + 2x2)
(-3(5 + 3x + 2x2) + 4x * (5 + 3x + 2x2)) = 0
((5 * -3 + 3x * -3 + 2x2 * -3) + 4x * (5 + 3x + 2x2)) = 0
((-15 + -9x + -6x2) + 4x * (5 + 3x + 2x2)) = 0
(-15 + -9x + -6x2 + (5 * 4x + 3x * 4x + 2x2 * 4x)) = 0
(-15 + -9x + -6x2 + (20x + 12x2 + 8x3)) = 0

Reorder the terms:
(-15 + -9x + 20x + -6x2 + 12x2 + 8x3) = 0

Combine like terms: -9x + 20x = 11x
(-15 + 11x + -6x2 + 12x2 + 8x3) = 0

Combine like terms: -6x2 + 12x2 = 6x2
(-15 + 11x + 6x2 + 8x3) = 0

Solving
-15 + 11x + 6x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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